If the polynomials az3 42z2 3z – 4 and z3 4z a leave the same remainder when divided by z – 3, find the value of a asked in Class IX Maths by priya12 ( 12,184 points) polynomialsExpand following, using suitable identities (–2x 5y – 3z)^2 CBSE CBSE (English Medium) Class 9 Textbook Solutions 50 Important Solutions 1 Question Bank Solutions 7801 Concept Notes & Videos 2 Syllabus Advertisement Remove all ads Expand (2x5y3z) 2 Share with your friends Share 2 it mean we have to multiply each term in braces with 2 we get 4x10y6z5 ;
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Expand (2x-y+3z)^2-(i) 9x 2 6xy y 2 (ii) 4y 2 – 4y 1 (iii) x 2 – Solution Ex 25 Class 9 Maths Question 4 Expand each of the following, using suitable identities (i) (x 2y 4z) 2 (ii) (2x y z) 2 (iii) (2x 3y 2z) 2 (iv) (3a – 7b c) 2 (v) (2x 5y – 3z) 2 (vi) 2 Solution Ex 25 Class 9 Maths Question 5 Factorise (i) 4x 2 9y 2 I62 x 2y 3z = 1 2x y 3z = 2 5x 5y 9z = 4 Free Practice With Testbook Mock Tests NDA 2/21 Mock Test a 1 x b 1 y c 1 z = d 1 a 2 x b 2 y c 2 z = d 2 If in the expansion of (x a)n, the sum of odd terms is P and the sum of even terms is Q, then the value of (x a)2n (x a)2n is
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2 Expand each of the following a) (x2)(x3) b) (ab)(c3) c) (y − 3)(y 2) d) (2x1)(3x−2) e) (3x− 1)(3x1) f) (5x− 1)(x− 5) g) (2p3q)(5p−2q) h) (x2)(2x2 − x− 1) Answers 1 a) 5x b) 2y −6 c) 12−4a d) 2xx2 e) pq 3p f) −6−3a g) st−s2 h) −2b6 i) 10ab15ac j) −2xy 5y2 2 a) x2 5x6 b) ac3abc3b c) y2 −Click here👆to get an answer to your question ️ Expand ( 2x 5y 3z )^2 using suitable identities Expand each of the following, using suitable identities (2x 5y 3z)2 Welcome to Sarthaks eConnect A unique platform where students can interact with teachers/experts/students to get solutions to their queries
Expression is (2x y 3z) 2 Formula used (a b c) 2 = a 2 b 2 c 2 2ab 2bc 2ca Calculation (2x y 3z) 2 ⇒ (2x) 2 (y) 2 (3z) 2 2(2x)(y) 2(y)(3z) 2(3z)(2x) ⇒ 4x 2 y 2 9z 2 4xy 6yz 12xz−2x (x − y − z) = −2×2 2xy 2xz Example 3 Expand −3a 2 (3 − b) Solution Apply the distributive property to multiply −3a 2 by all terms within the parenthesisExample 2 Expand −2x (x − y − z) Solution Multiply −2x by all terms inside the parenthesis and change the operators accordingly;
Simplify (2xy)(3x4y) Expand using the FOIL Method Tap for more steps Apply the distributive property Apply the distributive property Apply the distributive property Simplify and combine like terms Tap for more steps Simplify each term expand 2x y 3z 2 Mathematics TopperLearningcom ey4kyrl55Free system of equations calculator solve system of equations stepbystep
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Solution Steps ( 2 x 3 z ) ^ { 2 } ( 2 x − 3 z) 2 Use binomial theorem \left (ab\right)^ {2}=a^ {2}2abb^ {2} to expand \left (2x3z\right)^ {2} Use binomial theorem ( a − b) 2 = a 2 − 2 a b b 2 to expand ( 2 x − 3 z) 2 4x^ {2}12xz9z^ {2} 4 x 2 − 1 2 x z 9 z 2Solution for xy – 2z = 1 5y 2z = 3 2x – y 3z = 2 By Cramer's rule, solve the system Q 2)Two strains of bacteria are growing in seperate petri dishes Intitially, there are strain A 300To ask Unlimited Maths doubts download Doubtnut from https//googl/9WZjCW If number of terms in the expansion of `(x 2y 3z)^n` are 45, then n is equal to
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(3x y 2z) 2 = 9x 2 y 2 4z 2 6xy 4yz 12xz So, the expansion of (3x y 2z) 2 is 9x 2 y 2 4z 2 6xy 4yz 12xz Question 8 Expand (x 2y 3z) 2 Solution (x 2y 3z) 2 = x 2 (2y) 2 (3z) 2 2(x)(2y) 2(2y)(3z) 2(x)(3z) (x 2y 3z) 2 = x 2 4y 2 9z 2 4xy 12yz 6xz So, the expansion of (x 2y color(red)((2x3)^4 = 16x^4 96x^3 216x^2 216x 81) > Write out the fifth row of Pascal's triangle and make the appropriate substitutions Pascal's triangle is (from wwwkidshondurascom) The numbers in the fifth row are 1, 4, 6, 4, 1 They are the coefficients of the terms in a fourth order polynomial Your polynomial is (2x3)^4 Let y =2x and z=3Polynomials Zigya App Expand the following (i) (x 2y 3z)2 (ii) (i) (x 2y 3z) 2 = { (x) ( 2y) ( 3z)} 2 = (x) 2 ( 2y) 2 ( 3z) 2 2 (x) ( 2y) 2 (2y) (3z)2 (3z) (x) = x 2 4y 2 9z 2 4xy 12yz 6zx 321 Views
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You can put this solution on YOUR website! Stepbystep explanation /* We know the algebraic identity (abc)²=a²b²c²2ab2bc2ca */ Here , (x2y3z)² = x² (2y) (3z)² = x²(2y)²(3z)²2×x(2y)2×(2y)(3z)2×(3z)x = x²4y²9z²4xy12yz6zx Therefore,Free expand & simplify calculator Expand and simplify equations stepbystep This website uses cookies to ensure you get the best experience By using this
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Ex 25, 4 Expand each of the following, using suitable identities (x 2y 4z)2 (x 2y 4z)2 Using (a b c)2 = a2 b2 c2 2ab 2bc 2ac Where a = x , bUnlock this full stepbystep solution!Expanding Logarithms – Properties, Examples, and Explanation There are instances when we need to expand logarithmic expressions before simplifying or manipulating the entire expression
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The other tutor's answer is incorrect Use binomial expansion to expand the following (2x3y)4 The first term is (2x) the second term is (3y) The power is 4 so write " (2x) (3y)" one more than 4, that is, 5 times (2x) (3y) (2x) (3y) (2x) (3y) (2x) (3y) (2x) (3y) Give the first factor Give possible expressions for the length and breadth of each of the following rectangles, in which their areas are given (i) Area 25a2 – 35a 12 (ii) Area 35y2 13y – 12 Solution (i) We have, area of rectangle = 25a 2 – 35a12 = 25a 2 – a – 15a12 Transcribed image text 1) Solve the system y z x=1 2y 3z — 2x = 1 y 4z x = 0 2) A train travels 600 mi in the same time that a truck travels 550 mi Find the rate of each vehicle if the train's average rate is 5 mph faster than that of the truck 3 4 y 3) Simplify using the power rule and leave your answer with positive exponents y 4) Write using scientific notation 5) Expand
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Expand following, using suitable identities (x 2y 4z) 2 Advertisement Remove all ads Solution Show Solution It is known that, (x y z) 2 = x 2 y 2 z 2 2xy 2yz 2zx (x 2y 4z) 2 = x 2 (2y) 2 (4z) 2 2(x)(2y) 2(2y)(4z) 2(4z)(x) = x 2 4y 2 16z 2Calculadora gratuita para decompor e simplificar – Decompor e simplificar equações passo a passoThis term will be of the form n x 3 y 2 z 3 w for some integer n, so its "coefficient" is n w We can expand ( 2 x 3 y − 4 z w) 9 = ( ( 2 x 3 y − 4 z) w) 9 as ( 2 x 3 y − 4 z) 9 9 w ( 2 x 3 y − 4 z) 8 , so n is equal to 9 times the coefficient of x 3 y 2 z 3 in the expansion of ( 2 x 3 y
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View Full Answer it mean we have to multiply each term in braces with 2 we get 4x10y6z 0 ;Expand each of the following, using suitable identities ( 2x 3y 2z)^2 > 8th > Maths > Squares and Square Roots > Finding Square of a Number(√2x2y√3z)^2 Report Posted by Prashant Lamba 3 years, 1 month ago CBSE > Class 08 > Mathematics 0 answers ANSWER
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NCERT Solution For Class 9 Maths Chapter 2 Polynomials Here, x = 2x y = −y z = z (2x−yz)2 = 2(2x)2(−y)z2(2×2x×−y)(2×−y×z)(2×z×2x) = 24x2y2z –4xy–2yz4xz (iii) (−2x3y2z)2 Solution Using identity, 2(xyz)2 = x 2y z 2xy2yz2zx Here, x = −2xSolution Consider system of linear equations x y z = 2 2x y z = 3 3x 2y kz = 4 This system of equations has a unique solution if determinant of above system is non zero ie $\begin{vmatrix}1&1&1\\ 2&1&1\\ 3&2&k\end{vmatrix} \neq 0$ $\Rightarrow $ 1(k 2) 1(2k 3) 1(4 3) 0 $\Rightarrow $ k 2 2k 3 4 3 $\neq$ 0 $\Rightarrow $ k $\neq$ 0See Details For More You Can Retry This Question Below Expand "f(x) = In((2x^3 Sqrt(y))/(3z^9))' X Submit Question Problem Set 33 Expanding Logarithms Score 074 2/4 Answered Question 3 < > Expand 'f(x) = In((3 X^4 Y^5)/(z^10))' Submit Question
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Class9»Maths Polynomials Expand (2xy3z)2 Share with your friends Share6 VarunRawat answered this 2xy3z2=2xy3z2=2x2 y2 3z2 22xy 2y3z 23z2x=4x2 y2Now use the multinomial theorem to figure out the respective multinomial coefficients which should be 1, 3, 3, 3, 6, 3, 1, 3, 3, 1 in that order Now expand using everything to get ( 2 x − y 3 z) 3 = ( 2 x) 3 3 ( 2 x) 2 ( − y) 3 ( 2 x) 2 ( 3 z) 3 ( 2 x) ( − y) 2 6 ( 2 x) ( − y) ( 3 z) 3 ( 2 x) ( 3 z) 2 ( − y) 3 3 ( − y) 2 ( 3 z) 3 ( − y) ( 3 z) 2 ( 3 z) 3This calculator can be used to expand and simplify any polynomial expression
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Since V = x y − 3 1 x 2 y − 3 2 x y 2, V x = y − 3 2 x y − 3 2 y 2 = 0 and V y = x − 3 1 x 2 − 3 4 x y = 0 Multiplying by 3 in each equation and dividing by y in the first Maximize x^2y^2z^2 subject to x2y3z=4 and x,y,z\geq 0Expand by using suitable identity ; Bihar Board Class 9th Maths Solutions Chapter 2 Polynomials Ex 25 Textbook Questions and Answers BSEB Bihar Board Class 9th Maths Solutions Chapter 2 Polynomials Ex 25 Question 1 Use suitable identities to find the
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To ask Unlimited Maths doubts download Doubtnut from https//googl/9WZjCW Expand each of the following, using suitable identities(i) `(x2y4z)^2` (ii) color(red)((2x1)^5 = 32x^580x^480x^340x^210x1) Write out the sixth row of Pascal's triangle and make the appropriate substitutions Pascal's triangle is (from wwwkidshondurascom) The numbers in the fifth row are 1, 5, 10, 10, 5, 1 They are the coefficients of the terms in a fifth order polynomial (xy)^5 = x^5 5x^4y 10x^3y^2 10x^2y^3 5xy^4 yShow intermediate steps Learn how to solve special products problems step by step online Expand the expression (x2y3z)^2 Expand the trinomial using the formula \left (abc\right)^2 = a^2 b^2 c^2 2ab 2ac 2bc Multiply 2 times 2 Multiply 2 times 3 Multiply 2 times 2
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Log 2 (8) log 2 ( x4) – log 2 (5) = 3 4 log 2 ( x) – log 2 (5) Each log now finally contains only one thing, and the first log term has been simplified to a numerical value, so this expression is fully expanded Then my final answer is 3 4log 2 ( x) – log 2 (5) Content Continues Below Binomial Theroem 0 19 6 534 Find the coefficient of x^3 y^3 z^2 in the expansion of (xyz)^8 MathCuber 0 users composing answersExpandcalculator Expand (2x3y3z) (xyz3) he Related Symbolab blog posts Middle School Math Solutions – Equation Calculator Welcome to our new "Getting Started" math solutions series Over the next few weeks, we'll be showing how Symbolab
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